F(t)=2t^2+4

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Solution for F(t)=2t^2+4 equation: 



(F)=2F^2+4

We move all terms to the left:

(F)-(2F^2+4)=0

We get rid of parentheses

-2F^2+F-4=0

a = -2; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·(-2)·(-4)
Δ = -31
Delta is less than zero, so there is no solution for the equation

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